C++ Template Lambda. Web foo.template operator () (); If the t t parameter.
C++ 에서 Lambda 와 Functional feature
Note that lambdatemplate is not a dependent name,. Web foo.template operator () (); The reason for this strange syntax is because: Auto lambdatemplate = [&] (const int v) { return foo<t1, t2> (v); If the t t parameter. Foo is a generic lambda which. Web if you need to explicitly specify the template arguments when calling a lambda, which i find is a common need in my use cases (e.g. Web c++14 introduced the generic lambda expression into the core language feature which allowed the lambda expression to accept any parameter in its parameter.
Note that lambdatemplate is not a dependent name,. Foo is a generic lambda which. The reason for this strange syntax is because: If the t t parameter. Note that lambdatemplate is not a dependent name,. Web if you need to explicitly specify the template arguments when calling a lambda, which i find is a common need in my use cases (e.g. Auto lambdatemplate = [&] (const int v) { return foo<t1, t2> (v); Web foo.template operator () (); Web c++14 introduced the generic lambda expression into the core language feature which allowed the lambda expression to accept any parameter in its parameter.
